document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28072>Question 28072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the first side of a tringle is 8cm shorter than the second side,the third side is 4 times as long as the first side. the perimiter is 26cm. find the lenght of the sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15317 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Second side = x<BR>\n" );
document.write( "First side = x-8<BR>\n" );
document.write( "THird side = 4(x-8)<BR>\n" );
document.write( "P=26<BR>\n" );
document.write( "  Together:\r<BR>\n" );
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document.write( "x+(x-8)+4(x-8)=26<BR>\n" );
document.write( "2x-8+4x-32=26<BR>\n" );
document.write( "6x-40=26<BR>\n" );
document.write( "6x=66<BR>\n" );
document.write( "x=11 (second sidde)\r<BR>\n" );
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document.write( "11-8= 3(first side)\r<BR>\n" );
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document.write( "4(11-3)=12 (third side)\r<BR>\n" );
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document.write( "Hence, the three sides are 3, 11, 12.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );