document.write( "Question 203002This question is from textbook Beginning Algebra
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document.write( ": I know how to do the problem I just cant figure out how to set the problem up(translate). Thank you.\r
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document.write( "21.How many gallons of a 12% solution must be mixed with a 20% solution to get 10 gallons of a 14% solution.\r
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document.write( "32.A movie theater has two ticket prices: $8 for adults and $5 for children. If the box office took in $4116 from sales of 600 tickets, how many tickets of each kind were sold? \n" );
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Algebra.Com's Answer #153149 by rfer(16322) ![]() You can put this solution on YOUR website! A) \n" ); document.write( "let x=12% solution \n" ); document.write( "let 10-x=20% solution \n" ); document.write( ".12x+.20(10-x)=.14(10) \n" ); document.write( ".12x-.20x=1.4-2 \n" ); document.write( "-.08x=-.6 \n" ); document.write( "x=7.5 \n" ); document.write( "7.5 gal of 12% \n" ); document.write( "2.5 gal of 20% \n" ); document.write( "-------------------- \n" ); document.write( "B) \n" ); document.write( "let x = adults \n" ); document.write( "let y = children \n" ); document.write( "8x+5y=4116 \n" ); document.write( "x+y=600 \n" ); document.write( "x=600-y \n" ); document.write( "----------------- \n" ); document.write( "8(600-y)+5y=4116 \n" ); document.write( "4800-8y+5y=4116 \n" ); document.write( "-3y=-684 \n" ); document.write( "y=228 \n" ); document.write( "---------------- \n" ); document.write( "x+y=600 \n" ); document.write( "x=600-228 \n" ); document.write( "x=372 \n" ); document.write( "---------------------- \n" ); document.write( "8*372+5*228= \n" ); document.write( "2976+1140=4116 \n" ); document.write( " |