document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202915>Question 202915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the shoe store has twice as many black shoes as it does brown shoes. the total number of shoes is 66. how many brown shoes are there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153117 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let BL = the number of black shoes and BR = the number of brown shoes.<BR>\n" );
document.write( "From the problem statement:<BR>\n" );
document.write( "1) BL = 2*BR  \"the shoe store has twice as many black shoes as it does brown shoes.\"<BR>\n" );
document.write( "2) BL+BR = 66  \"the total number of shoes is 66.\"<BR>\n" );
document.write( "Rewrite equation 2) as:<BR>\n" );
document.write( "BL = 66-BR and substitute this into equation 1).<BR>\n" );
document.write( "(66-BR) = 2*BR Add BR to both sides of the equation.<BR>\n" );
document.write( "66 = 3*BR  Divide both sides by 3.<BR>\n" );
document.write( "22 = BR<BR>\n" );
document.write( "There are 22 brown shoes. </SPAN>\n" );
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