document.write( "Question 202948: Factor: 64x^3+27y^3 \n" ); document.write( "
Algebra.Com's Answer #153103 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"64x%5E3%2B27y%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%29%5E3%2B%283y%29%5E3\" Rewrite \"64x%5E3\" as \"%284x%29%5E3\". Rewrite \"27y%5E3\" as \"%283y%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B3y%29%28%284x%29%5E2-%284x%29%283y%29%2B%283y%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B3y%29%2816x%5E2-12xy%2B9y%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"64x%5E3%2B27y%5E3\" factors to \"%284x%2B3y%29%2816x%5E2-12xy%2B9y%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"64x%5E3%2B27y%5E3=%284x%2B3y%29%2816x%5E2-12xy%2B9y%5E2%29\"
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