document.write( "Question 202939: Solve:29=3e^2x \n" ); document.write( "
Algebra.Com's Answer #153088 by RAY100(1637)\"\" \"About 
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29 = 3e^(2x)
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\n" ); document.write( "29/3 =e^(2x)
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\n" ); document.write( "remember,, ln(e^a)=aln(e)=a(1) =a
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\n" ); document.write( "ln(29/3) =ln (e^2x)= 2x ln(e) = 2x
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\n" ); document.write( "2.269 = 2x
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\n" ); document.write( "1.134 = x
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\n" ); document.write( "29 = 3e^(2*1.134) = 29,,,,,ok
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