document.write( "Question 202900: Which one of the following is true? (1) The function, f(x)=2x^2+1/x^2-1, does not have a horizontal asymptote. (2) The graph of a rational function cannot have x-intercepts. (3) The horizontal asymptote for the graph of y=4x-1/x+3 is x=-3. (4) The graph of f(x)=2x+4/x^2-4 has only one vertical asymptote. THIS IS A TOUGH ONE....HELP. \n" ); document.write( "
Algebra.Com's Answer #153063 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "1) Has a horizontal asymptote at \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) The graph of a rational function can have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3) As in #1, the horizontal asymptote is at \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4) This one looks false on the face of it, because you would expect a vertical asymptote at any zero of the denominator polynomial. However, note that -2 is a zero of the denominator, but it is also a zero of the numerator. Hence, while there is a discontinuity at -2, there is no asymptote. In order to prove it, you need a little trick from the Calculus called L'Hôpital's Rule. It says that if:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and if\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So for the function given in #4,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "not \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore #4 is the true statement.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |