document.write( "Question 202882: Solve. Ln(2x^2+0.5)=0 \n" ); document.write( "

Algebra.Com's Answer #153048 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve. Ln(2x^2+0.5)=0
\n" ); document.write( "2x^2+0.5 = e^0
\n" ); document.write( "2x^2 + 0.5 = 1
\n" ); document.write( "2x^2 = 1/2
\n" ); document.write( "x^2 = 1/4
\n" ); document.write( "x = 1/2 or x = -1/2
\n" ); document.write( "===========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

\n" );