document.write( "Question 28026: The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle.\r
\n" ); document.write( "\n" ); document.write( "(I tried to double the diagonal dimensions and multiply L*W, but I could not come up with the right answer) \n" ); document.write( "
Algebra.Com's Answer #15303 by venugopalramana(3286)\"\" \"About 
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The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle.\r
\n" ); document.write( "\n" ); document.write( "(I tried to double the diagonal dimensions and multiply L*W, but I could not come up with the right answer)
\n" ); document.write( "area =LW=45..............OR...........L=45/W
\n" ); document.write( "DIAGONAL =SQUARE ROOT OF (L^2+W^2)=10...SQUARING BOTH SIDES ...
\n" ); document.write( "L^2+W^2=100
\n" ); document.write( "45^2/W^2+W^2=100
\n" ); document.write( "LET W^2=X
\n" ); document.write( "2025/X+X=100
\n" ); document.write( "2025+X^2=100X
\n" ); document.write( "X^2-100X+2025=0
\n" ); document.write( "USING THE QUADRATIC FORMULA
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=28.2O55
\n" ); document.write( "HENCE W =SQRT(X)=5.31
\n" ); document.write( "L=45/5.31=8.47\r
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