document.write( "Question 202857: Separate 71 into two parts such that 40 exceeds ⅔ of one part as much as the other exceeds 16. \n" ); document.write( "
Algebra.Com's Answer #153019 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! 1) x + y =71,,,,,y=71-x \n" ); document.write( ". \n" ); document.write( "2) (2/3 )x -40 = 16-y = 16-(71-x) = -55 +x \n" ); document.write( ". \n" ); document.write( "(-1/3) x = -15 \n" ); document.write( ". \n" ); document.write( "x=45,,,,,y=71-45=26 \n" ); document.write( ". \n" ); document.write( "check,,,(1) 45 +26 =71,,,ok \n" ); document.write( ". \n" ); document.write( "(2) 2/3 (45)-40 =16-26,,,,,-10 =-10,,,,,ok \n" ); document.write( " |