document.write( "Question 200454: Hi!\r
\n" ); document.write( "\n" ); document.write( "Find an exponential function passing through (1,3) and (3,4.32)\r
\n" ); document.write( "\n" ); document.write( "thanks for the study help!
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Algebra.Com's Answer #153003 by jsmallt9(3758)\"\" \"About 
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Exponential functions are in the form: \"y+=+k%2Aa%5Ex\" where k and a are constants. So our task is to find the values of k and a.

\n" ); document.write( "We can do this by using the points we know will fit the equation: (1, 3) and (3, 4.32). Let's start with the first point. Substituting the x and y coordinates from (1, 3) for the x and y in \"y+=+k%2Aa%5Ex\" we get:
\n" ); document.write( "\"%283%29+=+k%2Aa%5E%281%29\"
\n" ); document.write( "Simplifying we get:
\n" ); document.write( "\"3+=+k%2Aa\"
\n" ); document.write( "Dividing both sides by a we get:
\n" ); document.write( "\"3%2Fa+=+k\"

\n" ); document.write( "Now let's do it with the second point. We will use the x and y from (3, 4.32) and the \"value\" we just got for k: 3/a. Substituting these 3 values into \"y+=+k%2Aa%5Ex\" we get:
\n" ); document.write( "\"%284.32%29+=+%283%2Fa%29%2Aa%5E3\"
\n" ); document.write( "Simplifying we get:
\n" ); document.write( "\"4.32+=+3a%5E2\"
\n" ); document.write( "Dividing both sides by 3 we get:
\n" ); document.write( "\"1.44+=+a%5E2\"
\n" ); document.write( "Finding the square root of both sides we get:
\n" ); document.write( "\"1.2+=+a\" or \"-1.2+=+a\"
\n" ); document.write( "Since we usually want a > 0 then we may reject the a = -1.2.
\n" ); document.write( "As a fraction 1.2 is 6/5. If a = 6/5 then k = 3/(6/5) = 5/2. So our exponential equation is:
\n" ); document.write( "\"y+=+%285%2F2%29%286%2F5%29%5Ex\" or ,as decimals, \"y+=+2.5%281.2%29%5Ex\")
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