document.write( "Question 202806: The perimeter of a lot is 190 m. The width is one fourth the length. Find the dimensions.\r
\n" ); document.write( "\n" ); document.write( "Could you please help me leabel them like 1,2,1a,2a,3,3 into 1,etc. \n" ); document.write( "

Algebra.Com's Answer #152980 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle:
\n" ); document.write( "1) $\"P+=+2%28L%2BW%29\"$ where L = length and W = width.
\n" ); document.write( "2) $\"W+=+%281%2F4%29L\"$ \"The width (W) is one fourth the length (L).\" Multiply both sides by 4.
\n" ); document.write( "2a) $\"4W+=+L\"$ Into equation 1) Substitute $\"P+=+190\"$ and $\"L+=+4W\"$
\n" ); document.write( "1a) $\"190+=+2%284W%2BW%29\"$ Divide both sides by 2.
\n" ); document.write( "1b) $\"95+=+%285W%29\"$ Divide both sides by 5.
\n" ); document.write( "1c) $\"highlight%2819+=+W%29\"$ and..
\n" ); document.write( "2b) $\"L+=+4W\"$
\n" ); document.write( "2c) $\"L+=+4%2819%29\"$
\n" ); document.write( "2d) $\"highlight%28L+=+76%29\"$
\n" ); document.write( "The length is 76m. and the width is 19m.
\n" ); document.write( "Check:
\n" ); document.write( " $\"P+=+2%28L%2BW%29\"$ Substitute $\"L+=+76\"$ and $\"W+=+19\"$
\n" ); document.write( " $\"P+=+2%2876%2B19%29\"$ Evaluate.
\n" ); document.write( " $\"P+=+2%2895%29\"$
\n" ); document.write( " $\"P=++190\"$ OK! \n" ); document.write( "

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