document.write( "Question 202797: theater owner charges $3.00 of admission, there is an average attendance of 100 people. for every .10 increase in the admission price , there is a loss of 2 customers from the average number.
\n" ); document.write( "Teacher is asking what admission price should be charged in order to maximize revenue?
\n" ); document.write( "what is the maximum revenue?\r
\n" ); document.write( "\n" ); document.write( "I set it up
\n" ); document.write( "R(x)= (3.00-.10x)(100-2x)
\n" ); document.write( "am I on the right track
\n" ); document.write( "not sure what to due next
\n" ); document.write( "thanks
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #152964 by stanbon(75887)\"\" \"About 
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theater owner charges $3.00 of admission, there is an average attendance of 100 people. for every .10 increase in the admission price , there is a loss of 2 customers from the average number.
\n" ); document.write( "Teacher is asking what admission price should be charged in order to maximize revenue?
\n" ); document.write( "what is the maximum revenue?
\n" ); document.write( "I set it up
\n" ); document.write( "R(x)= (3.00-.10x)(100-2x)
\n" ); document.write( "am I on the right track
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Revenue = unit price*attendance
\n" ); document.write( "R = (300-10x)(100-2x)
\n" ); document.write( "R = 30000 - 600x -1000x + 20x^2
\n" ); document.write( "R = 20x^2 - 1600x + 30000
\n" ); document.write( "---------------
\n" ); document.write( "Maximum R occurs when x = -b/2a = 1600/(40) = 40
\n" ); document.write( "When x = 40 the ticket price is 300-40 = $2.60
\n" ); document.write( "=====================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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