document.write( "Question 202790: coul you help me about this equation?
\n" ); document.write( " $\"log%288%2C%28x-1%29%29%2B1%2F3=log%288%2C%28x%2B7%29%29\"$ \n" ); document.write( "

Algebra.Com's Answer #152955 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Applying \"log rules\":
\n" ); document.write( " $\"log%288%2C%28x-1%29%29%2B1%2F3=log%288%2C%28x%2B7%29%29\"$
\n" ); document.write( " $\"log%288%2C%28x-1%29%29+-+log%288%2C%28x%2B7%29%29+=+-1%2F3\"$
\n" ); document.write( " $\"log%288%2C%28x-1%29%2F%28x%2B7%29%29+=+-1%2F3\"$
\n" ); document.write( " $\"%28x-1%29%2F%28x%2B7%29+=+8%5E%28-1%2F3%29\"$
\n" ); document.write( " $\"%28x-1%29%2F%28x%2B7%29+=+1%2F8%5E%281%2F3%29\"$
\n" ); document.write( " $\"%28x-1%29%2F%28x%2B7%29+=+1%2F2\"$
\n" ); document.write( " $\"2%28x-1%29+=+%28x%2B7%29\"$
\n" ); document.write( " $\"2x-2+=+x%2B7\"$
\n" ); document.write( " $\"x-2+=+7\"$
\n" ); document.write( " $\"x+=+9\"$
\n" ); document.write( " \n" ); document.write( "

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