document.write( "Question 202643: Solve. Log (〖3x〗^2 + 2x +2)=0.84509 \n" ); document.write( "
Algebra.Com's Answer #152953 by jsmallt9(3759)\"\" \"About 
You can put this solution on YOUR website!
If the problem is not: \"log%28%283x%5E2+%2B2x+%2B+2%29%29+=+0.84509\", please repost it
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\n" ); document.write( "If the problem is \"log%28%283x%5E2+%2B2x+%2B+2%29%29+=+0.84509\", start by rewriting it in exponential form:
\n" ); document.write( "\"3x%5E2+%2B+2x+%2B+2+=+10%5E%280.84509%29\"
\n" ); document.write( "\"10%5E%280.84509%29+=+6.9998704114807013\" Since this is so close to 7 I think you are supposed to use 7. (If not then you will have to use the quadratic formula on the equation with this very long decimal!?)
\n" ); document.write( "\"3x%5E2+%2B+2x+%2B+2+=+7\"
\n" ); document.write( "Subtracting 7 from both sides:
\n" ); document.write( "\"3x%5E2+%2B+2x+-+5+=+0\"
\n" ); document.write( "Factoring:
\n" ); document.write( "\"%283x+%2B+5%29%28x+-+1%29+=+0\"
\n" ); document.write( "The only way for a product to be zero is if one of the factors is zero. So:
\n" ); document.write( "\"%283x+%2B+5%29+=+0\" or \"%28x+-+1%29+=+0\"
\n" ); document.write( "Solving these we get:
\n" ); document.write( "\"x+=+%28-5%29%2F3\" or \"x+=+1\"
\n" ); document.write( "
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