document.write( "Question 202750: An investor put 75% of his money into a 6% simple annual interest account and 25% of his money into a 5% annual interest account. Find the amount invested if the total amount of annual interest earned is $4312.50. What is the amount invested at 6%? Round to the nearest dollar. \n" ); document.write( "
Algebra.Com's Answer #152932 by Earlsdon(6294)\"\" \"About 
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Let x = the total amount invested.
\n" ); document.write( "75% of the total is 0.75x
\n" ); document.write( "25% of the total is 0.25x
\n" ); document.write( "6% of the first amount is (0.75x)(0.06) = 0.045x
\n" ); document.write( "5% of the second amount is (0.25x)(0.05) = 0.0125x
\n" ); document.write( "Add these two amounts and set them equal to $4321.50
\n" ); document.write( "0.045x+0.0125x = $4321.50 Add the x-terms on the left side.
\n" ); document.write( "0.0575x = $4321.50 Divide both sides by 0.0575
\n" ); document.write( "x = $75,156.52 This is the total amount invested.
\n" ); document.write( "75% of $75,156.52 = $56,367.40 This is the amount invested at 6%
\n" ); document.write( "Rounded to the nearest dollar, this would be: $56,367.00
\n" ); document.write( "25% of $75,156.52 = $18,789.13 This is the amount invested at 5%
\n" ); document.write( "Rounded to the nearest dollar, this would be: $18,789.00
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