document.write( "Question 202755: Need help with this symbol manipulation problem please.
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document.write( "S=2B+Ph
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document.write( "Solve for h.\r
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document.write( "My try: 2B/Ph
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document.write( "h=2B? \n" );
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Algebra.Com's Answer #152926 by PRMath(133)![]() ![]() ![]() You can put this solution on YOUR website! Need help with this symbol manipulation problem please. \n" ); document.write( "S=2B+Ph \n" ); document.write( "Solve for h. \n" ); document.write( "My try: 2B/Ph \n" ); document.write( "h=2B?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Close. You sort of lost track of your \"S\" variable. Keep thinking: \"How can I isolate the \"h\"?\" \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, here's the problem.......\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 2B+ Ph You have a +2B so let's subtract it from both sides......\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you have:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S - 2B = Ph Now how do we isolate the \"h\"? Well, you are multiplying between the P and the h. Sooooo, to sort of \"get rid\" of the P, you have to figure out how to \"un-do\" the multiplying between the P and the h. What is the OPPOSITE of multiplying? Try DIVIDING.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S-2B/P = h\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does this make sense to you? I hope so.... \n" ); document.write( " |