document.write( "Question 202755: Need help with this symbol manipulation problem please.
\n" ); document.write( "S=2B+Ph
\n" ); document.write( "Solve for h.\r
\n" ); document.write( "\n" ); document.write( "My try: 2B/Ph
\n" ); document.write( "h=2B?
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Algebra.Com's Answer #152926 by PRMath(133)\"\" \"About 
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Need help with this symbol manipulation problem please.
\n" ); document.write( "S=2B+Ph
\n" ); document.write( "Solve for h.
\n" ); document.write( "My try: 2B/Ph
\n" ); document.write( "h=2B?\r
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\n" ); document.write( "\n" ); document.write( "Close. You sort of lost track of your \"S\" variable. Keep thinking: \"How can I isolate the \"h\"?\" \r
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\n" ); document.write( "\n" ); document.write( "So, here's the problem.......\r
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\n" ); document.write( "\n" ); document.write( "S = 2B+ Ph You have a +2B so let's subtract it from both sides......\r
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\n" ); document.write( "\n" ); document.write( "Now you have:\r
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\n" ); document.write( "\n" ); document.write( "S - 2B = Ph Now how do we isolate the \"h\"? Well, you are multiplying between the P and the h. Sooooo, to sort of \"get rid\" of the P, you have to figure out how to \"un-do\" the multiplying between the P and the h. What is the OPPOSITE of multiplying? Try DIVIDING.\r
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\n" ); document.write( "\n" ); document.write( "S-2B/P = h\r
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\n" ); document.write( "\n" ); document.write( "Does this make sense to you? I hope so....
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