document.write( "Question 202755: Need help with this symbol manipulation problem please.
\n" ); document.write( "S=2B+Ph
\n" ); document.write( "Solve for h.\r
\n" ); document.write( "\n" ); document.write( "My try: 2B/Ph
\n" ); document.write( "h=2B?
\n" ); document.write( "

Algebra.Com's Answer #152925 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
S=2B+Ph
\n" ); document.write( "Solve for h

\n" ); document.write( "When you see the phrase: \"solve for \" it means \"use Algebra to manipulate the equation until the variable is by itself on one side of the equation.

\n" ); document.write( "In you problem it means: Manipulate S=2B+Ph until h is by itself. In other words we want the equation to look like:
\n" ); document.write( "h = [some-expression]
\n" ); document.write( "or
\n" ); document.write( "[some-expression] = h
\n" ); document.write( "Since the h is already on the right side we will aim for:
\n" ); document.write( "[some-expression] = h

\n" ); document.write( "To get the h by itself we need to make the 2B and the P disappear, using proper Algebra

\n" ); document.write( "We'll start by subtracting 2B from both sides:
\n" ); document.write( "S - 2B = 2B + Ph - 2B
\n" ); document.write( "The 2B's on the right cancel giving:
\n" ); document.write( "S - 2B = Ph
\n" ); document.write( "We've made the \"2B\" disappear\" from the right side! Now we will do the same with the \"P\". We can't, however, subtract \"P\" because \"P\" and \"Ph\" are not like terms! We can divide both sides by \"P\":
\n" ); document.write( "\"%28S+-+2B%29%2FP+=+%28Ph%29%2FP\"
\n" ); document.write( "On the right side the P's cancel:
\n" ); document.write( "\"%28S+-+2B%29%2FP+=+h\"
\n" ); document.write( "Guess what? We're done! We have \"h\" by itself so we have \"solved for h\".
\n" ); document.write( "
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