document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202733>Question 202733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rewrite ~ (p &#61658; ~q) using DeMorgan's laws </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152916 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The operator between p and ~q is not showing in my browser. So I am going to use \"@\" for the operator in the problem and \"$\" for the complementary operator. For example, if your operator is set union then \"@\" stands for this and \"$\" stands for set intersection.<br><BR>\n" );
document.write( "According to DeMorgan's law<BR>\n" );
document.write( "~(p @ ~q) = ~p $ ~~q = ~p $ q </SPAN>\n" );
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