document.write( "Question 202748: Can someone please help \r
\n" ); document.write( "\n" ); document.write( "dividing polynomials
\n" ); document.write( "(3x^3 – x^2 + 10^x – 4) ÷ (x + 3)
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Algebra.Com's Answer #152915 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Here's the long division:
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document.write( "    3x^2 + (-10x) + 40\r\n" );
document.write( "    ___________________________\r\n" );
document.write( "x+3/3x^3 + (-x^2) + 10x +  (-4)\r\n" );
document.write( "    3x^3 +  9x^2\r\n" );
document.write( "    ------------\r\n" );
document.write( "          -10x^2 +  10x \r\n" );
document.write( "          -10x^2 + -30x\r\n" );
document.write( "          -------------\r\n" );
document.write( "                    40x + (-4)\r\n" );
document.write( "                    40x + 120\r\n" );
document.write( "                    ----------\r\n" );
document.write( "                         -124\r\n" );
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\n" ); document.write( "As usual, when the remainder is not 0, you put it into the numerator of a fraction with the divisor in the denominator. So:
\n" ); document.write( "(3x^3 – x^2 + 10^x – 4) ÷ (x + 3) = \"3x%5E2+-+10x+%2B+40+%2B+%28-124%29%2F%28x%2B3%29\"
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