document.write( "Question 202745: Solve
\n" ); document.write( "9/10 (7+2x)+2 ≥ 14
\n" ); document.write( "--------------------
\n" ); document.write( "63/10 +9/5 x+2 ≥ 14
\n" ); document.write( "9/5x+83/10 ≥ 14
\n" ); document.write( "subtract 83/10
\n" ); document.write( "9/5x + 83/10-83/10 ≥ 14-83/10
\n" ); document.write( "9/5x ≥ ?/10 ( I'm a little confuse and could you help me out here please?)
\n" ); document.write( "Then multiply 5/9
\n" ); document.write( "9/5x * 5/9 ≥ ?/10*5/9 (And here?)
\n" ); document.write( "x ≥ ?
\n" ); document.write( "Thank you!\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #152908 by rfer(16322)\"\" \"About 
You can put this solution on YOUR website!
I like to use decimals when ever I can because it is easier.
\n" ); document.write( "9/10(7+2x)+2equal to or greater than 14
\n" ); document.write( "I will use = sign for ease of operation
\n" ); document.write( "9/10*7/10+2x/10+20/10=140/10
\n" ); document.write( "63/10+18x/10+20/10=140/10
\n" ); document.write( "18x/10=140/10-83/10
\n" ); document.write( "18/10(x)=57/10 remember, to divide, invert and multiply
\n" ); document.write( "x is equal to or greater than(57/10)(10/18)= 570/180=19/6=3.16
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( ".9(7+2x)+2=14
\n" ); document.write( "6.3+1.8x+2=14
\n" ); document.write( "1.8x=14-8.3
\n" ); document.write( "1.8x=5.7
\n" ); document.write( "x= is equal to or greater than 3.16 \n" ); document.write( "
\n" );