Algebra.Com's Answer #152891 by jsmallt9(3758)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
This much of your solution is good:
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document.write( "assume: 
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document.write( "giving: 2/(2-z)=6/(3+z)-3
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document.write( "Then we get a little off track finding the common denominator and subtracting. Since subtractions can cause so many problems I strongly encourage you to change subtractions to additions. So I would rewrite this as:
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document.write( "Now when we get the common denominator on the right side we might avoid the error you had:
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document.write( "We can solve this by cross-multiplying:
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document.write( "Subtracting 2z and 6 from both sides we get:
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document.write( "This will factor:
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document.write( "This gives solutions of z = 3 or z = -4/3.
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document.write( "Substituting back in for z we get:
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document.write( "Rewriting these in exponential form we get
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document.write( "If we want rationalized denominators we need a perfect cube in the denominator of the second solution:
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document.write( "Both of these answers check. (One should always check because we need to avoid extraneous solutions like those that would make the argument of a log function negative, make the radicand of an even-numbered root negative, denominators zero, etc.) \n" );
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