document.write( "Question 202646: Base of a triangle is 4cm greater than the height. The area is 30cm^2\r
\n" ); document.write( "\n" ); document.write( "Find the height and the length
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Algebra.Com's Answer #152879 by rajagopalan(174)\"\" \"About 
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Let height=x
\n" ); document.write( "then base=x+4
\n" ); document.write( "area=1/2*b*h
\n" ); document.write( "=(1/2)*(x)*(x+4)
\n" ); document.write( "=1/2(x^2+4x)
\n" ); document.write( "1/2(x^2+4x)=30
\n" ); document.write( "x^2+4x=30*2
\n" ); document.write( "x^2+4x-60=0
\n" ); document.write( "x^2+10x-6x-60=0
\n" ); document.write( "x(x+10)-6(x+10)=0
\n" ); document.write( "(x-6)(x+10)=0
\n" ); document.write( "giving x=6 or -10
\n" ); document.write( "Ignoring negative value
\n" ); document.write( "we get x=6
\n" ); document.write( "Answer:
\n" ); document.write( "Height=6
\n" ); document.write( "Base=10
\n" ); document.write( "Verification:
\n" ); document.write( "Area=1/2*b*h
\n" ); document.write( "=1/2*6*10
\n" ); document.write( "=3*10
\n" ); document.write( "=30 sq units
\n" ); document.write( "okay
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