document.write( "Question 202697: Suppose f(x) is an odd function whose domain is all real numvers. If the ordered pair(5,-2) is on the graph of y = f(x), then another ordered pair on the graph is (-2,5), (-5,-2), (-5,2), (2,-5)????? thanks for your assistance. \n" ); document.write( "

Algebra.Com's Answer #152872 by jim_thompson5910(35256) $\"\"$ $\"About$

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Recall that if a function f(x) is an odd function, then $\"f%28-x%29=-f%28x%29\"$ . Recall that f(x) is another way of saying \"y\". So when we plug in -x, we get -y. What this means in terms of the point (x,y), the point (-x,-y) is guaranteed to be on the function also. Since (x,y)=(5,-2), this means that (-x,-y)=(-5,2)\r
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\n" ); document.write( "\n" ); document.write( "So the answer is (-5,2)\r
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\n" ); document.write( "\n" ); document.write( "If none of the explanation above made any sense, all I did was change the signs of both coordinates. \n" ); document.write( "

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