document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202678>Question 202678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rachael hands in her 4th exam.  The scores on her first three exams were 75, 95, and 97.  What does she need to earn on the 4th exam to average at least a 90 on the four exams?  Construct an inequality with the variable x representing her 4th exam score, then solve the inequality for x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152858 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (75+95+97+x)/4=90<BR>\n" );
document.write( "267+x=90*4<BR>\n" );
document.write( "267+x=360<BR>\n" );
document.write( "x=360-267<BR>\n" );
document.write( "x=93 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );