document.write( "Question 202675: Find three consecutive integers such that the sum of the second and third exceeds half of the first by 33.
\n" ); document.write( "This is what I tried.... (x+1)+(x+2)=1/2x+33 which gave me x=30
\n" ); document.write( "

Algebra.Com's Answer #152855 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B1%29%2B%28x%2B2%29=%281%2F2%29x%2B33\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%2B3=%281%2F2%29x%2B33\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%282x%29%2B2%283%29=cross%282%29%28%281%2Fcross%282%29%29x%29%2B2%2833%29\" Multiply EVERY term by the LCD \"2\" to clear out the fraction.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x%2B6=x%2B66\" Multiply and simplify.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x=x%2B66-6\" Subtract \"6\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x-x=66-6\" Subtract \"x\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x=66-6\" Combine like terms on the left side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x=60\" Combine like terms on the right side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%2860%29%2F%283%29\" Divide both sides by \"3\" to isolate \"x\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=20\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solution is \"x=20\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This means that the first number is 20, the second is 21 (20+1=21), and the third is 22 (20+2=22)
\n" ); document.write( "
\n" );