document.write( "Question 202664: could sombody help me to solve it?\r
\n" ); document.write( "\n" ); document.write( "1/3.log(20,2x-1)=log(20,11)-2.log(20,(2x-1)^(1/3))+log(5,(log7,7))
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Algebra.Com's Answer #152846 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Quick note: \"log%287%2C%287%29%29=1\" and \"log%285%2C%281%29%29=0\". So \"log%285%2C%28log%287%2C%287%29%29%29%29=log%285%2C%281%29%29=0\". In other words, \"log%285%2C%28log%287%2C%287%29%29%29%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "So the expression \r
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\n" ); document.write( "\n" ); document.write( "simplifies to \r
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\n" ); document.write( "\n" ); document.write( " Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( " Rewrite the last log using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply\r
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\n" ); document.write( "\n" ); document.write( " Subtract \"log%2820%2C%2811%29%29\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( " Subtract \"%281%2F3%29log%2820%2C%282x-1%29%29\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-log%2820%2C%2811%29%29=%28-2%2F3-1%2F3%29log%2820%2C%282x-1%29%29\" Factor out the GCF \"log%2820%2C%282x-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-log%2820%2C%2811%29%29=%28-3%2F3%29log%2820%2C%282x-1%29%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-log%2820%2C%2811%29%29=-log%2820%2C%282x-1%29%29\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"log%2820%2C%2811%29%29=log%2820%2C%282x-1%29%29\" Multiply both sides by -1\r
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\n" ); document.write( "\n" ); document.write( "\"11=2x-1\" Since the bases of the logs are equal, this means that the arguments are equal.\r
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\n" ); document.write( "\n" ); document.write( "\"11%2B1=2x\" Add 1 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"12=2x\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"12%2F2=x\" Divide both sides by 2 to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6=x\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=6\"\r
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