document.write( "Question 202658This question is from textbook
\n" ); document.write( ": Decreasing Cube. Each of the three dimensions of a cube with sides of length S centimeters is decreased by a whole number of centimeters. The new volume in cubic centimeter is given my \r
\n" ); document.write( "\n" ); document.write( "V(s) = S^3-13s^2+54s-72\r
\n" ); document.write( "\n" ); document.write( "a) Find V(10)
\n" ); document.write( "b) If the new width is S-6 centimeters, then what are the new length and height
\n" ); document.write( "c) Find the volume when S=10 by multiplying the length, width, and height.\r
\n" ); document.write( "\n" ); document.write( "I am not very good at word problems and don't know how to write them out in ever detail like my instructor wants.\r
\n" ); document.write( "\n" ); document.write( "I am greatful for any help thank you
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Algebra.Com's Answer #152836 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
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\n" ); document.write( "\n" ); document.write( "\"V%28s%29=s%5E3-13s%5E2%2B54s-72\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=%2810%29%5E3-13%2810%29%5E2%2B54%2810%29-72\" Plug in \"s=10\" (ie replace each \"s\" with 10).\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=1000-13%2810%29%5E2%2B54%2810%29-72\" Cube \"10\" to get \"1000\".\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=1000-13%28100%29%2B54%2810%29-72\" Square \"10\" to get \"100\".\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=1000-1300%2B54%2810%29-72\" Multiply \"-13\" and \"100\" to get \"-1300\".\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=1000-1300%2B540-72\" Multiply \"54\" and \"10\" to get \"540\".\r
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\n" ); document.write( "\n" ); document.write( "\"V%2810%29=168\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"V=LWH\" Start with the volume equation.\r
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\n" ); document.write( "\n" ); document.write( "\"s%5E3-13s%5E2%2B54s-72=L%28s-6%29H\" Plug in the given expressions\r
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\n" ); document.write( "\n" ); document.write( "\"%28s%5E3-13s%5E2%2B54s-72%29%2F%28s-6%29=LH\" Divide both sides by \"s-6\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28s-6%29%28s%5E2-7s%2B12%29%29%2F%28s-6%29=LH\" Factor the numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%28%28s-6%29%29%28s%5E2-7s%2B12%29%29%2Fcross%28%28s-6%29%29=LH\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"s%5E2-7s%2B12=LH\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"LH=s%5E2-7s%2B12\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"LH=%28s-3%29%28s-4%29\" Factor\r
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\n" ); document.write( "\n" ); document.write( "So the new length and height are \"s-3\" and \"s-4\"\r
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\n" ); document.write( "\n" ); document.write( "c)\r
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\n" ); document.write( "\n" ); document.write( "I'll let you attempt this one on your own. Repost if you still need help.\r
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\n" ); document.write( "\n" ); document.write( "Note: the answer is going to be the same as the answer in part a) (so you'll have something to check)
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