document.write( "Question 202660: Hi, could you help me to solve these equations?
\n" ); document.write( "2^(2x+1) - 10.2^x=-12
\n" ); document.write( "log(4,[log(4,(log4,x))])=0
\n" ); document.write( "1/3.log(20,2x-1)=log(20,11)-2.log(20,(2x-1)^(1/3))+log(5,(log7,7))
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #152834 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to give you an idea on how to tackle these problems.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5E%282x%2B1%29-10%2A2%5Ex=-12\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5E%282x%29%2A2%5E1-10%2A2%5Ex=-12\" Break up the exponent using the identity \"x%5E%28y%2Bz%29=x%5E%28y%29%2Ax%5E%28z%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5E%282x%29%2A2-10%2A2%5Ex=-12\" Raise 2 to the first power to get 2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%2A2%5E%282x%29-10%2A2%5Ex=-12\" Rearrange the terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%2A%282%5Ex%29%5E2-10%2A2%5Ex=-12\" Rewrite \"2%5E%282x%29\" as \"%282%5Ex%29%5E2\" using the identity \"%28x%5E%28y%29%29%5Ez=x%5E%28y%2Az%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let \"z=2%5Ex\". So \"z%5E2=%282%5Ex%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2z%5E2-10z=-12\" Replace \"%282%5Ex%29%5E2\" with \"z%5E2\". Replace \"2%5Ex\" with \"z\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2z%5E2-10z%2B12=0\" Add 12 to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"2z%5E2-10z%2B12\" is in the form of \"Az%5E2%2BBz%2BC\" where \"A=2\", \"B=-10\", and \"C=12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"z\":\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%28-%28-10%29+%2B-+sqrt%28+%28-10%29%5E2-4%282%29%2812%29+%29%29%2F%282%282%29%29\" Plug in \"A=2\", \"B=-10\", and \"C=12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+sqrt%28+%28-10%29%5E2-4%282%29%2812%29+%29%29%2F%282%282%29%29\" Negate \"-10\" to get \"10\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+sqrt%28+100-4%282%29%2812%29+%29%29%2F%282%282%29%29\" Square \"-10\" to get \"100\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+sqrt%28+100-96+%29%29%2F%282%282%29%29\" Multiply \"4%282%29%2812%29\" to get \"96\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+sqrt%28+4+%29%29%2F%282%282%29%29\" Subtract \"96\" from \"100\" to get \"4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+sqrt%28+4+%29%29%2F%284%29\" Multiply \"2\" and \"2\" to get \"4\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B-+2%29%2F%284%29\" Take the square root of \"4\" to get \"2\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2810+%2B+2%29%2F%284%29\" or \"z+=+%2810+-+2%29%2F%284%29\" Break up the expression. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%2812%29%2F%284%29\" or \"z+=++%288%29%2F%284%29\" Combine like terms. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+3\" or \"z+=+2\" Simplify. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions (in terms of 'z') are \"z+=+3\" or \"z+=+2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now recall that we let \"z=2%5Ex\". So let's use this to find the solutions in terms of \"x\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+3\" Start with the first solution in terms of 'z'\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+3\" Plug in \"z=2%5Ex\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5Ex%29%29+=+log%2810%2C%283%29%29\" Take the log of both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%282%29%29+=+log%2810%2C%283%29%29\" Rewrite the first log using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+log%2810%2C%283%29%29%2Flog%2810%2C%282%29%29\" Divide both sides by \"log%2810%2C%282%29%29\" to isolate \"x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+log%282%2C%283%29%29\" Use the change of base formula to simplify\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+2\" Start with the second solution in terms of 'z'\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+2\" Plug in \"z=2%5Ex\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5Ex%29%29+=+log%2810%2C%282%29%29\" Take the log of both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%282%29%29+=+log%2810%2C%282%29%29\" Rewrite the first log using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+log%2810%2C%282%29%29%2Flog%2810%2C%282%29%29\" Divide both sides by \"log%2810%2C%282%29%29\" to isolate \"x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+log%282%2C%282%29%29\" Use the change of base formula to simplify\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+1\" Evaluate the log base 2 of 2 to get 1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=======================================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+log%282%2C%283%29%29\" or \"x+=+1\" \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );