document.write( "Question 202641: A certain bacterial infection has 110,000 organisms at 12:00pm. At 12:30 pm the population was 140,000. If this growth rate has been steady, when did the infection start? \n" ); document.write( "
Algebra.Com's Answer #152830 by stanbon(75887)\"\" \"About 
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A certain bacterial infection has 110,000 organisms at 12:00pm. At 12:30 pm the population was 140,000. If this growth rate has been steady, when did the infection start?
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\n" ); document.write( "A(t) = Ao*(r)^t
\n" ); document.write( "---
\n" ); document.write( "r is the rate of growth
\n" ); document.write( "t is the time in minutes
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\n" ); document.write( "140,000 = 110,000*r^(30)
\n" ); document.write( "14/11 = r^(30)
\n" ); document.write( "Take the log:
\n" ); document.write( "30*log(r) = log(14/11)
\n" ); document.write( "log(r) = [log(14/11)]/30
\n" ); document.write( "log(r) = 0.0034911784
\n" ); document.write( "r = 10^0.0034911784
\n" ); document.write( "r = 1.008071133 per minute
\n" ); document.write( "-------------------------------
\n" ); document.write( "1 = 110,000(1.008071133)^t
\n" ); document.write( "1.008071133)^t = 110,000^-1
\n" ); document.write( "t*log(1.998071133) = -log(110,000)
\n" ); document.write( "t = -16.7705 minutes
\n" ); document.write( "----------------------------
\n" ); document.write( "12:00 - 16.77 minutes is approximately 11:43 am
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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