document.write( "Question 202617: A rectangle is half as wide as it is long. If both the length and width are decreased by 2 cm, the area decreases by 68 cm(squared) . Find the length of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #152829 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let the original length = L and the original width = W, so that the original area: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now, if we subtract 2 cm from the length (L-2) and 2 cm from the width (W-2) the area is decreased by 68 sq.cm. (A-68). Lets find the new area: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The original length of the rectangle is 24 cm. \n" ); document.write( "Check: \n" ); document.write( "Original area: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now the new area is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The difference is: \n" ); document.write( " |