document.write( "Question 27975: Could you please help me with this problem\r
\n" ); document.write( "\n" ); document.write( "Solve for x\r
\n" ); document.write( "\n" ); document.write( "log( 2x+10)=log 4x
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Algebra.Com's Answer #15278 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
Solve for x\r
\n" ); document.write( "\n" ); document.write( "log( 2x+10)=log 4x----(1)
\n" ); document.write( "Applying the rule:[log p to base b =log q to the same base b implies p=q]
\n" ); document.write( "we have (2x+10) = 4x
\n" ); document.write( " 10 = 4x-2x
\n" ); document.write( "10 = 2x
\n" ); document.write( "That is 2x = 10
\n" ); document.write( "Therefor x = 10/2 = 5
\n" ); document.write( "Answer: x = 5
\n" ); document.write( "You can verify orally!
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