document.write( "Question 202496: What is the vertex for the parabola whose equation is f(x)=-3(x+12)^2-14? \n" ); document.write( "
Algebra.Com's Answer #152767 by RAY100(1637)\"\" \"About 
You can put this solution on YOUR website!
f(x) =y=-3(x+12)^2 -14
\n" ); document.write( ".
\n" ); document.write( "(y +14) = -3 (x+12)^2
\n" ); document.write( ".
\n" ); document.write( "standard form is,,,,,,(y-k) = A (x-h)^2, with (h,k) as vertex
\n" ); document.write( ".
\n" ); document.write( "from above h= -12,,,and k = -14,,,
\n" ); document.write( ".
\n" ); document.write( "therefore, vertex is ( -12,-14)
\n" ); document.write( ".
\n" ); document.write( "to check,,,A= (-3) which means it is pointed down
\n" ); document.write( ".
\n" ); document.write( "check on either side of vertex for confirmation
\n" ); document.write( ".
\n" ); document.write( "@ x= -13, y= -3(-13+12)^2 -14,,y= -17,,,which is lower than -14
\n" ); document.write( ".
\n" ); document.write( "@ x=-11, y= -3(-11+12)^2 -14,,,y = -17,,,which again is lower than -14.
\n" ); document.write( ".
\n" ); document.write( "This confirms vertex, and downward pointing of parabola.
\n" ); document.write( " \n" ); document.write( "
\n" );