document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28000>Question 28000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the quadratic equation x2-3x+2=0  perform the following tasks:\r<BR>\n" );
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document.write( "solve by factoring.\r<BR>\n" );
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document.write( "solve by completing the square.  Since it is x square, should i devide both sides by x?\r<BR>\n" );
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document.write( "solve by using the quadratic equasion. \r<BR>\n" );
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document.write( "I don't necesarily want it answered, I just need to know how to do these equations. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15276 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the quadratic equation x2-3x+2=0 perform the following tasks: <BR>\n" );
document.write( "solve by factoring. <BR>\n" );
document.write( "solve by completing the square. Since it is x square, should i devide both sides by x? <BR>\n" );
document.write( "solve by using the quadratic equasion. \r<BR>\n" );
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document.write( "I don't necesarily want it answered, I just need to know how to do these equations.\r<BR>\n" );
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document.write( "completing the square method<BR>\n" );
document.write( "x2-3x+2=0<BR>\n" );
document.write( "[x^2-2X(3/2)X(x)]+2=0<BR>\n" );
document.write( "Notice that the first two terms have been brought under the structure a^2 -2ab. So you need b^2 to complete the square and here b^2-(3/2)^2 = 9/4 <BR>\n" );
document.write( "Therefore<BR>\n" );
document.write( "[x^2-2X(3/2)X(x)+(9/4-9/4)]+2=0<BR>\n" );
document.write( "[x^2-2X(3/2)X(x)+(9/4]+(-9/4+2)=0<BR>\n" );
document.write( "(x-3/2)^2 = 9/4-2 = 1/4<BR>\n" );
document.write( "Taking the sqroot<BR>\n" );
document.write( "(x-3/2)= +1/2 or -1/2<BR>\n" );
document.write( "(x-3/2)= +1/2  gives x = 1/2+3/2 = 2<BR>\n" );
document.write( "(x-3/2)= -1/2  gives x = -1/2+3/2 = 1<BR>\n" );
document.write( "Answer: x = 2 and x=1\r<BR>\n" );
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document.write( "solve by using the quadratic equasion<BR>\n" );
document.write( "x2-3x+2=0<BR>\n" );
document.write( "x2+[(-2x)+(-x)]+2=0  <BR>\n" );
document.write( "[splitting the middle term into two parts <BR>\n" );
document.write( "whose multiplication is the product of the square term and the constant term.<BR>\n" );
document.write( "-3x = (-2x) + (-x) so that (-2x)X(-x) = +(2x^2) = (x^2)X(2)]<BR>\n" );
document.write( "x2-2x-x+2=0  (you may straight away write this without writing the previous. the previous step is for your self study)<BR>\n" );
document.write( "(x2-2x)-x+2=0 <BR>\n" );
document.write( "x(x-2)-(x-2)=0 (why pull out -1 ? just to get (x-2) as a common factor.)<BR>\n" );
document.write( "xp-p=0  where p = (x-2)<BR>\n" );
document.write( "p(x-1) = 0<BR>\n" );
document.write( "(x-2)(x-1) = 0<BR>\n" );
document.write( "(x-2) = 0 gives x = 2 and (x-1) = 0 gives x = 1  \r<BR>\n" );
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document.write( " </SPAN>\n" );
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