document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202517>Question 202517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dawing at least 1 spade in a series of 4 consecutive draws when the card is returned to the deck after each draw and the deck is reshuffled. What has confused me is that we only need to get 1 spade in 4 draws. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152757 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dawing at least 1 spade in a series of 4 consecutive draws when the card is returned to the deck after each draw and the deck is reshuffled. What has confused me is that we only need to get 1 spade in 4 draws.<BR>\n" );
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document.write( "Note: P(no spade on a single draw) = (3/4)<BR>\n" );
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document.write( "P(at least 1 spade in 4 draws) = 1 - P(no spades in 4 draws)<BR>\n" );
document.write( "= 1 - (3/4)^4<BR>\n" );
document.write( "= 1 - (81/256)<BR>\n" );
document.write( "= 175/256<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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