document.write( "Question 27985: Find the domain of y=x+3if the range is {-1,1,3,5}
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Algebra.Com's Answer #15273 by sdmmadam@yahoo.com(530)\"\" \"About 
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Find the domain of y=x+3if the range is {-1,1,3,5}
\n" ); document.write( "I don't get this
\n" ); document.write( "The range set that is the set of images is {-1,1,3,5}
\n" ); document.write( "The correspondence is y = x+3 (which is clearly a 1-1 function that is every image y is having a single preimage x)
\n" ); document.write( "so x here is from (x+3) = y
\n" ); document.write( "x = y-3 ---(*)
\n" ); document.write( "If y = -1 then x = (-1)-3 = -4
\n" ); document.write( "Verification: What gets mapped onto (-1) under y = x+3 gives us (-4)as answer and of course (-4) = 3 = -1
\n" ); document.write( "Thus if y=-1, then x is -4
\n" ); document.write( "Similarly y=1 in (*) gives x = -2
\n" ); document.write( "y=3 in (*) gives x = 0
\n" ); document.write( "y=5 in (*) gives x = 2
\n" ); document.write( "Thus the set that gets mapped onto {-1,1,3,5}
\n" ); document.write( " under y = f(x) = x+3 is given by
\n" ); document.write( "{-4,-2,0,2}\r
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