document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202366>Question 202366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist mixes a 20% solution and a 50% solution to obtain a 40% solution.  If 300g of solution was obtained, how much of each type of the original solutions were used?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152684 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=20% mix<BR>\n" );
document.write( "let 300-x=50% mix<BR>\n" );
document.write( ".2x+.5(300-x)=.4(300)<BR>\n" );
document.write( ".2x+150-.5x=120<BR>\n" );
document.write( "-.3x=-30<BR>\n" );
document.write( "x=100 gal<BR>\n" );
document.write( "300-x=200 gal </SPAN>\n" );
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