document.write( "Question 202429: If G lies on the perpendicular bisector of segment AB, AG = +3x, and
\n" ); document.write( "BG= -10x+140, find AG.\r
\n" ); document.write( "\n" ); document.write( "I know that AG=BG, and I need help solving this equation... x^2+3x = -10x+140\r
\n" ); document.write( "\n" ); document.write( "I got it down to x^2+13x = 140 and I don't know where to go from here.
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Algebra.Com's Answer #152659 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm not sure that you have the right equation (I don't have access to the drawing), but here's how you would solve it.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x=-10x%2B140\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B10x-140=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B13x-140=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2%2B13x-140\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=13\", and \"C=-140\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2813%29+%2B-+sqrt%28+%2813%29%5E2-4%281%29%28-140%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=13\", and \"C=-140\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+sqrt%28+169-4%281%29%28-140%29+%29%29%2F%282%281%29%29\" Square \"13\" to get \"169\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+sqrt%28+169--560+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-140%29\" to get \"-560\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+sqrt%28+169%2B560+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%28169--560%29\" as \"sqrt%28169%2B560%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+sqrt%28+729+%29%29%2F%282%281%29%29\" Add \"169\" to \"560\" to get \"729\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+sqrt%28+729+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B-+27%29%2F%282%29\" Take the square root of \"729\" to get \"27\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-13+%2B+27%29%2F%282%29\" or \"x+=+%28-13+-+27%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2814%29%2F%282%29\" or \"x+=++%28-40%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+7\" or \"x+=+-20\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+7\" or \"x+=+-20\" \r
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\n" ); document.write( "\n" ); document.write( "Note: If you only need the positive solution, then just ignore \"x+=+-20\"
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