document.write( "Question 202388: Scott wants to make 15 L of a 68% acid solution by mixing together a 75% acid solution and a 60% acid solution. How much of each solution must be used? \n" ); document.write( "

Algebra.Com's Answer #152646 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of 75% solution used
\n" ); document.write( "Then 15-x=amount of 60% solution used
\n" ); document.write( "The amount of pure acid in the 75% solution (0.75x) plus the amount of pure acid in the 60% solution (0.60(15-x)) has to equal the amount of pure acid in the final mixture (0.68*15), so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.75x+0.60(15-x)=0.68*15 get rid of parens
\n" ); document.write( "0.75x+9-0.60x=10.2 subtract 9 from each side
\n" ); document.write( "0.75x+9-9-0.60x=10.2-9 colect like terms
\n" ); document.write( "0.15x=1.2 divide each side by 0.15
\n" ); document.write( "x=8 L------------------------amount of 75% solution used
\n" ); document.write( "15-x=15-8=7 L-----------------amount of 60% solution used\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.75*8+0.60*7=0.68*15\r
\n" ); document.write( "\n" ); document.write( "6+4.2=10.2
\n" ); document.write( "10.2=10.2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "

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