document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202358>Question 202358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The standard form of a circle whose center is (-3,2) and radius 4 is  (1)(x-3)^2+(y+2)^2=16  (2)(x+3)^2+(y-2)^2=16  (3) (x-3)^2+(y+2)^2=4  (4) (x+3)^2+(y-2)^2=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152610 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> standard  for  for  a  circle  is,,,,(x-h)^2 +(y-k)^2 = r^2<BR>\n" );
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document.write( "center  is  (h,k),,  in this  case (-3,2),,,or  h=(-3),,k=(2)<BR>\n" );
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document.write( "r=4,,,,r^2 =16<BR>\n" );
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document.write( "{ x-(-3)}^2 + {y-(2)}^2 = {4}^2<BR>\n" );
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document.write( "(x+3)^2 +(y-2)^2 =16<BR>\n" );
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document.write( "this  matches,,,( 2 )  above<BR>\n" );
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