document.write( "Question 202376This question is from textbook Algebra Structure and Method
\n" ); document.write( ": Solve One eighth of the square toor of 7 less than a number is 2 What is the number. Am I on the right track with 1/8 sqrt x - 7 = 2 and where do I go from here.\r
\n" ); document.write( "\n" ); document.write( "Thanks for any help
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Algebra.Com's Answer #152608 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Looks like what you want is:
\n" ); document.write( "\"sqrt%28x-7%29%2F8=2\"
\n" ); document.write( "multiply both sides of the equation by 8 to get:
\n" ); document.write( "\"sqrt%28x-7%29+=+16\"
\n" ); document.write( "square both sides of the equation to get:
\n" ); document.write( "\"x-7+=+16%5E2\"
\n" ); document.write( "which becomes:
\n" ); document.write( "\"x-7+=+256\"
\n" ); document.write( "-----
\n" ); document.write( "add 7 to both sides of the equation to get:
\n" ); document.write( "\"x+=+263\"
\n" ); document.write( "-----
\n" ); document.write( "your answer should be x = 263.
\n" ); document.write( "-----
\n" ); document.write( "substitute in the original equation to prove the answer is good.
\n" ); document.write( "-----
\n" ); document.write( "\"sqrt%28263-7%29%2F8+=+2\"
\n" ); document.write( "which becomes:
\n" ); document.write( "\"sqrt%28256%29%2F8+=+2\"
\n" ); document.write( "which becomes:
\n" ); document.write( "\"16%2F8+=+2\"
\n" ); document.write( "which becomes:
\n" ); document.write( "\"2+=+2\"
\n" ); document.write( "which is true so the answer is good.
\n" ); document.write( "the answer is:
\n" ); document.write( "x = 256
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