document.write( "Question 202376This question is from textbook Algebra Structure and Method
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document.write( ": Solve One eighth of the square toor of 7 less than a number is 2 What is the number. Am I on the right track with 1/8 sqrt x - 7 = 2 and where do I go from here.\r
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document.write( "Thanks for any help \n" );
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Algebra.Com's Answer #152608 by Theo(13342) You can put this solution on YOUR website! Looks like what you want is: \n" ); document.write( " \n" ); document.write( "multiply both sides of the equation by 8 to get: \n" ); document.write( " \n" ); document.write( "square both sides of the equation to get: \n" ); document.write( " \n" ); document.write( "which becomes: \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "add 7 to both sides of the equation to get: \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "your answer should be x = 263. \n" ); document.write( "----- \n" ); document.write( "substitute in the original equation to prove the answer is good. \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( "which becomes: \n" ); document.write( " \n" ); document.write( "which becomes: \n" ); document.write( " \n" ); document.write( "which becomes: \n" ); document.write( " \n" ); document.write( "which is true so the answer is good. \n" ); document.write( "the answer is: \n" ); document.write( "x = 256 \n" ); document.write( " \n" ); document.write( " |