document.write( "Question 28010: just learning algebra at the age of 60 stuck on the following\r
\n" ); document.write( "\n" ); document.write( "2+X OVER 2 = 1- X OVER 3 WHAT IS THE VALUE OF X
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Algebra.Com's Answer #15260 by bmauger(101)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2Bx%29%2F2=%281-x%29%2F3\"
\n" ); document.write( "This can be solved by cross multiplying based on the fact that:
\n" ); document.write( "\"a%2Fb=c%2Fd\" can be rewritten by multiplying together the diagonals and setting them equal like:
\n" ); document.write( "\"ad=bc\" For your problem write:
\n" ); document.write( "\"3%2A%282%2Bx%29=2%2A%281-x%29\"Distribute on both sides:
\n" ); document.write( "\"6%2B3x=2-2x\"Add 2x to both sides:
\n" ); document.write( "\"6%2B5x=2\"Subtract 6 from both sides:
\n" ); document.write( "\"5x=-4\"Divide both sides by 5:
\n" ); document.write( "\"x=-4%2F5\"
\n" ); document.write( "Double check:
\n" ); document.write( "\"2%2Bhighlight%28-4%2F5%29%2F2=%281-highlight%28-4%2F5%29%29%2F3\"
\n" ); document.write( "\"%286%2F5%29%2F2=%289%2F5%29%2F3\"
\n" ); document.write( "\"6%2F10=9%2F15\"
\n" ); document.write( "\"3%2F5=3%2F5\"Check
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