document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202337>Question 202337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Algebra 2: How do i find an equation with the given slope and points for example : Slope = -2: passing through (3, -1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152567 by </B><A HREF=/tutors/aboutme.mpl?userid=PRMath><B>PRMath(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PRMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Algebra 2: How do i find an equation with the given slope and points for example : Slope = -2: passing through (3, -1)\r<BR>\n" );
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document.write( "I'm not very good with making formulas look good on this website yet so when I say x1, I mean \"x\" subscript 1.  Similarly, when I say y1, I mean \"y\" subscript 1, k? :-)\r<BR>\n" );
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document.write( "Now that you know that, let's begin.  \r<BR>\n" );
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document.write( "When you know the slope and a point that the line goes through, you can find the equation of the line by using the POINT SLOPE equation of a line.  Here it is:\r<BR>\n" );
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document.write( "y - y1 = m(x - x1)\r<BR>\n" );
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document.write( "All you have to do is fill in the info you have.  In this case, you know the slope is -2.  In the above equation, \"m\" refers to slope, so that means:  <BR>\n" );
document.write( "m = -2.\r<BR>\n" );
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document.write( "The line passes thru the point (3, -1)    The number 3 is your x1 and the number -1 is your y1.  All you have to do now is \"plug\" in the values for your variables.  So let's do that now:\r<BR>\n" );
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document.write( "Remember:  m = -2<BR>\n" );
document.write( "Passes thru (3, -1)\r<BR>\n" );
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document.write( "POINT SLOPE equation of a line:  y - y1 = m(x - x1)\r<BR>\n" );
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document.write( "y - (-1) = -2(x - 3)<BR>\n" );
document.write( "y + 1 = -2(x - 3)  \r<BR>\n" );
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document.write( "See where I plugged in the slope and the x1 and y1 values?   Sometimes the problem ends there, but other times, you have to put the equation in the SLOPE INTERCEPT form of a line, which is y = mx + b.  Sooooo, if you are supposed to do that, you need to solve for y and you'll be fine.  Let's try that now by taking the first few steps above and doing some more calculations..........\r<BR>\n" );
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document.write( "y - (-1) = -2(x - 3)<BR>\n" );
document.write( "y + 1 = -2(x - 3)  <BR>\n" );
document.write( "y + 1 = -2x + 6  (Distributed the -2)<BR>\n" );
document.write( "y = -2x + 6 - 1  (Subtracted 1 from both sides)<BR>\n" );
document.write( "y = -2x + 5  \r<BR>\n" );
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document.write( "Now you have the answer in slope/intercept form.  \r<BR>\n" );
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document.write( "I hope this is helpful. :-)<BR>\n" );
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