document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202309>Question 202309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> john and peter are 448 meters apart. they start walking towords each other at the same time. peter walks at a speed of 3 m/s and john at 4 m/s. <BR>\n" );
document.write( "1. after how many minutes will they meet?<BR>\n" );
document.write( "2. what distance will each have walked when they meet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152532 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Use the relationship between distance, rate, and time:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ d = rt\">\r<BR>\n" );
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document.write( "Which can be expressed as time as a function of distance and rate as:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ t = \frac{d}{r}\">\r<BR>\n" );
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document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large d\"> represent the distance John walked, and then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 448 - x\"> represents the distance that Peter walked. So, using the given rates we can say, with regard to John:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ t = \frac{d}{4}\">\r<BR>\n" );
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document.write( "And with regard to Peter:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ t = \frac{448-d}{3}\">\r<BR>\n" );
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document.write( "Since they started at the same time, and the end of both trips is the time that they met, <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\"> is identical for both equations.  That means we can equate the right-hand sides of the two equations:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{d}{4} = \frac{448-d}{3}\">\r<BR>\n" );
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document.write( "Solve this equation for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large d\">.  Hint: Cross-multiply, distribute, collect like terms, and then divide by the resulting coefficient on d.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large d\"> will be the distance that John walked.  Subtract this value from 448 to get the distance that Peter walked.  That will answer question 2.\r<BR>\n" );
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document.write( "Divide the distance John walked by 4 or divide the distance Peter walked by 3 (they are both the same result) to get the number of seconds that will have elapsed when they met.  Divide this result by 60 to get the number of minutes for question 1.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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