document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27976>Question 27976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me with this problem<BR>\n" );
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document.write( "Use: log of 3 in base x = .275 and log of 5 in base x = .732\r<BR>\n" );
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document.write( "Find: log of 15 to the 2 power in base x\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15247 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  log of 3 in base x = .275 and log of 5 in base x = .732\r<BR>\n" );
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document.write( "Find: log of 15 to the 2 power in base x\r<BR>\n" );
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document.write( "WE USE THE FORMULAE<BR>\n" );
document.write( "LOG A TO BASE X = LOG(A)/LOG(X)... AND ...LOG (A*B) = LOG(A)+LOG(B)...AND...<BR>\n" );
document.write( "LOG (A)^N=N*LOG(A)<BR>\n" );
document.write( "log of 3 in base x = .275 =LOG(3)/LOG(X)................I<BR>\n" );
document.write( "log of 5 in base x = .732 =LOG(5)/LOG(X)...............II<BR>\n" );
document.write( "log of 15 to the 2 power in base x =LOG(15)^2/LOG(X)=LOG(3*5)/LOG(X)<BR>\n" );
document.write( "=2*{LOG(3)+log(5)}/LOG(X)=2*{LOG(3)/LOG(X) + LOG(5)/LOG(X)}=2*(0.275 + 0.732) = 2*1.007=2.014 \r<BR>\n" );
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