document.write( "Question 202163: Find 3 consecutive numbers where the product of the smaller two numbers is 37 less than the square of the largest number. \n" ); document.write( "

Algebra.Com's Answer #152412 by vleith(2983) $\"\"$ $\"About$

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We'll assume they mean three consecutive integers.
\n" ); document.write( "Let x be the smallest. Then the other two numbers are $\"x%2B1\"$ and $\"x%2B2\"$
\n" ); document.write( "Given
\n" ); document.write( " $\"x%2A%28x%2B1%29+=+%28x%2B2%29%5E2+-+37\"$
\n" ); document.write( " $\"x%5E2+%2B+x+=+x%5E2+%2B+4x+%2B+4+-+37\"$
\n" ); document.write( " $\"x+=+4x+-+33\"$
\n" ); document.write( " $\"-3x+=+-33\"$
\n" ); document.write( " $\"x+=+11\"$
\n" ); document.write( "So the numbers are 11, 12 and 13.
\n" ); document.write( "Check your answer:
\n" ); document.write( "Does 11*12 = 13^2 - 37??? \n" ); document.write( "

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