document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=202142>Question 202142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank can be filled by one inlet pipe in 15 minutes . it takes an outlet pipe 75 minutes to drain the tank. if the outlet pipe is left open by accident, how long would it take to fill the tank ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152403 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If it takes 15 minutes to fill the tank and 75 minutes to empty the tank then the flow in is 5 times as fast as the flow out (=75/15).\r<BR>\n" );
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document.write( "Based on the speed of the outflow we have five times as much going in giving an overall filling up rate of four times the emptying rate or four fifths of the filling rate. (5 in  minus 1 out = 4 in).\r<BR>\n" );
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document.write( "Therefore the time to fill the tank with the filling and emptying happening together will be:\r<BR>\n" );
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document.write( "Based on filling speed\r<BR>\n" );
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document.write( "5/4 of 15 (because it is going at 4/5 of the rate and will take 5/4 of the time)\r<BR>\n" );
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document.write( "Or\r<BR>\n" );
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document.write( "Based on emptying speed\r<BR>\n" );
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document.write( "1/4 of 75 (because it is going at 4 times the rate and therefore will take 1/4 of the time)\r<BR>\n" );
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document.write( "Both give the answer of 75/4 = 18.75 minutes (18 minutes, 45 seconds). </SPAN>\n" );
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