document.write( "Question 202105: what is the first step i should take to solve the formula:3x6squared-2 o ------------ 6 \n" ); document.write( "
Algebra.Com's Answer #152375 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that the equation is \"%283x%5E2-2%29%2F6=0\" (it's very hard to read)\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-2%29%2F6=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-2=6%2A0\" Multiply both sides by 6.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-2=0\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2=0%2B2\"Add \"2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2=2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%282%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%282%2F3%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%282%2F3%29\" or \"x=-sqrt%282%2F3%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%286%29%2F3\" or \"x=-sqrt%286%29%2F3\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%28sqrt%286%29%29%2F%283%29\" or \"x=-%28sqrt%286%29%29%2F%283%29\".\r
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