document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27932>Question 27932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph f(x)=/x+2/. Note that f(x) is not one to one. Restrict the domain of f(x)     so that it does not have an inverse </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15229 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plot y=x+2 for x>= -2...a straight line\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The portion of y=x+2 below x=-2 is mirrored in the x-axis, creating a V-shaped graph. Algebraically, you are plotting y=-(x+2).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I think you mean restrict the domain of f(x) so that it DOES have an inverse.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Domain could be all values of x, so long as x>=-2. Or the domain could be all values of x, so long as x<= -2.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Either set of x-values is a valid domain for the function.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );