document.write( "Question 27934: Soybean meal is 16% protein. Corn meal is 10% protein. How much of each type should be mixed to bet a 15-lb mixture that is 12% protein? \n" ); document.write( "

Algebra.Com's Answer #15228 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the required number of pounds of 16%-protein soybean meal
\n" ); document.write( "15-x = the required number of pounds of 10%-protein corn meal.
\n" ); document.write( "You want x lbs of 16%-protein (0.16x) plus (15-x) lbs of 0.10%-protein (0.10(15-x)) to equal 15 lbs of 12% (0.12)(15) of mixture.
\n" ); document.write( "Change the percents to their eqivalent decimals and write the equation.\r
\n" ); document.write( "\n" ); document.write( " $\"0.16x+%2B+0.10%2815-x%29+=+0.12%2815%29\"$ Simplify and solve for x.
\n" ); document.write( " $\"0.16x+%2B+1.5+-+0.1x+=+1.8\"$ Combine the x-terms.
\n" ); document.write( " $\"0.06x+%2B+1.5+=+1.8\"$ Subtract 1.5 from both sides of the equation.
\n" ); document.write( " $\"0.06x+=+0.3\"$ Divide both sides by 0.06
\n" ); document.write( " $\"x+=+5\"$ \r
\n" ); document.write( "\n" ); document.write( "You will need 5 lbs of 16%-protein soybean meal and 10 lbs of 10%-protein corn meal to make a 15-lb mixture that is 12% protein. \n" ); document.write( "

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