document.write( "Question 202013: Could you help me about this ? :
\n" ); document.write( "Ben can paint a house in 36 hours. Carlos can pint the same house in 24 hours. They started working together but after 12 hours Ben quit. How much time was necessary for Carlos to finish the job alone?
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Algebra.Com's Answer #152274 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let's first find the hourly rate of each painter:
\n" ); document.write( "If Ben can paint the entire house in 36 hours, then he can paint \"1%2F36\" of the house in 1 hour.
\n" ); document.write( "If Carlos can paint the entire house in 24 hours, then he can paint \"1%2F24\" of the house in 1 hour.
\n" ); document.write( "Working together, Ben & Carlos can paint \"%281%2F36%29%2B%281%2F24%29+=+5%2F72\" of the house in 1 hour.
\n" ); document.write( "In 12 hours they can paint \"%2812%29%2A%285%2F72%29+=+5%2F6\" of the house, which leaves only \"1%2F6\" of the house to finish.
\n" ); document.write( "Now the question, how long will it take Carlos to finish the house?
\n" ); document.write( "Well, Carlos can do \"1%2F24\" in 1 hour, so you can let x = the number of hours Carlos needs and form a proportion:
\n" ); document.write( "\"1%2F6+=+x%2F24\" Multiply the first fraction by \"4%2F4\" to get the common denominator of 24.
\n" ); document.write( "\"%284%2F4%29%2A%281%2F6%29+=+x%2F24\" Evaluate.
\n" ); document.write( "\"4%2F24+=+x%2F24\" so...
\n" ); document.write( "\"x+=+4\"
\n" ); document.write( "Carlos needs 4 hours to finish the job.
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